Integrand size = 27, antiderivative size = 73 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\cos ^6(c+d x)}{6 a d}-\frac {\sin ^3(c+d x)}{3 a d}+\frac {2 \sin ^5(c+d x)}{5 a d}-\frac {\sin ^7(c+d x)}{7 a d} \]
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Time = 0.09 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2914, 2645, 30, 2644, 276} \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {\sin ^7(c+d x)}{7 a d}+\frac {2 \sin ^5(c+d x)}{5 a d}-\frac {\sin ^3(c+d x)}{3 a d}-\frac {\cos ^6(c+d x)}{6 a d} \]
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Rule 30
Rule 276
Rule 2644
Rule 2645
Rule 2914
Rubi steps \begin{align*} \text {integral}& = \frac {\int \cos ^5(c+d x) \sin (c+d x) \, dx}{a}-\frac {\int \cos ^5(c+d x) \sin ^2(c+d x) \, dx}{a} \\ & = -\frac {\text {Subst}\left (\int x^5 \, dx,x,\cos (c+d x)\right )}{a d}-\frac {\text {Subst}\left (\int x^2 \left (1-x^2\right )^2 \, dx,x,\sin (c+d x)\right )}{a d} \\ & = -\frac {\cos ^6(c+d x)}{6 a d}-\frac {\text {Subst}\left (\int \left (x^2-2 x^4+x^6\right ) \, dx,x,\sin (c+d x)\right )}{a d} \\ & = -\frac {\cos ^6(c+d x)}{6 a d}-\frac {\sin ^3(c+d x)}{3 a d}+\frac {2 \sin ^5(c+d x)}{5 a d}-\frac {\sin ^7(c+d x)}{7 a d} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.93 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\sin ^2(c+d x) \left (105-70 \sin (c+d x)-105 \sin ^2(c+d x)+84 \sin ^3(c+d x)+35 \sin ^4(c+d x)-30 \sin ^5(c+d x)\right )}{210 a d} \]
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Time = 0.26 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.96
method | result | size |
derivativedivides | \(-\frac {\frac {\left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {2 \left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{2}+\frac {\left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {\left (\sin ^{2}\left (d x +c \right )\right )}{2}}{a d}\) | \(70\) |
default | \(-\frac {\frac {\left (\sin ^{7}\left (d x +c \right )\right )}{7}-\frac {\left (\sin ^{6}\left (d x +c \right )\right )}{6}-\frac {2 \left (\sin ^{5}\left (d x +c \right )\right )}{5}+\frac {\left (\sin ^{4}\left (d x +c \right )\right )}{2}+\frac {\left (\sin ^{3}\left (d x +c \right )\right )}{3}-\frac {\left (\sin ^{2}\left (d x +c \right )\right )}{2}}{a d}\) | \(70\) |
parallelrisch | \(\frac {15 \sin \left (7 d x +7 c \right )+35 \sin \left (3 d x +3 c \right )+63 \sin \left (5 d x +5 c \right )-525 \sin \left (d x +c \right )-525 \cos \left (2 d x +2 c \right )-35 \cos \left (6 d x +6 c \right )-210 \cos \left (4 d x +4 c \right )+770}{6720 a d}\) | \(85\) |
risch | \(-\frac {5 \sin \left (d x +c \right )}{64 a d}+\frac {\sin \left (7 d x +7 c \right )}{448 d a}-\frac {\cos \left (6 d x +6 c \right )}{192 a d}+\frac {3 \sin \left (5 d x +5 c \right )}{320 d a}-\frac {\cos \left (4 d x +4 c \right )}{32 a d}+\frac {\sin \left (3 d x +3 c \right )}{192 d a}-\frac {5 \cos \left (2 d x +2 c \right )}{64 a d}\) | \(118\) |
norman | \(\frac {\frac {2 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}+\frac {2 \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}-\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}-\frac {2 \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}+\frac {4 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}+\frac {4 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d a}+\frac {52 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}+\frac {52 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}+\frac {122 \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}+\frac {122 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{15 d a}+\frac {74 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{35 d a}+\frac {74 \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{35 d a}+\frac {712 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}+\frac {712 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{105 d a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{8} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}\) | \(297\) |
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Time = 0.26 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.81 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {35 \, \cos \left (d x + c\right )^{6} - 2 \, {\left (15 \, \cos \left (d x + c\right )^{6} - 3 \, \cos \left (d x + c\right )^{4} - 4 \, \cos \left (d x + c\right )^{2} - 8\right )} \sin \left (d x + c\right )}{210 \, a d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1530 vs. \(2 (54) = 108\).
Time = 32.28 (sec) , antiderivative size = 1530, normalized size of antiderivative = 20.96 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\text {Too large to display} \]
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Time = 0.21 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.95 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {30 \, \sin \left (d x + c\right )^{7} - 35 \, \sin \left (d x + c\right )^{6} - 84 \, \sin \left (d x + c\right )^{5} + 105 \, \sin \left (d x + c\right )^{4} + 70 \, \sin \left (d x + c\right )^{3} - 105 \, \sin \left (d x + c\right )^{2}}{210 \, a d} \]
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Time = 0.30 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.95 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=-\frac {30 \, \sin \left (d x + c\right )^{7} - 35 \, \sin \left (d x + c\right )^{6} - 84 \, \sin \left (d x + c\right )^{5} + 105 \, \sin \left (d x + c\right )^{4} + 70 \, \sin \left (d x + c\right )^{3} - 105 \, \sin \left (d x + c\right )^{2}}{210 \, a d} \]
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Time = 10.01 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.14 \[ \int \frac {\cos ^7(c+d x) \sin (c+d x)}{a+a \sin (c+d x)} \, dx=\frac {\frac {{\sin \left (c+d\,x\right )}^2}{2\,a}-\frac {{\sin \left (c+d\,x\right )}^3}{3\,a}-\frac {{\sin \left (c+d\,x\right )}^4}{2\,a}+\frac {2\,{\sin \left (c+d\,x\right )}^5}{5\,a}+\frac {{\sin \left (c+d\,x\right )}^6}{6\,a}-\frac {{\sin \left (c+d\,x\right )}^7}{7\,a}}{d} \]
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